An open water conduit is to be cut in the shape of an isosceles trapezium and lined
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An open water conduit is to be cut in the shape of an isosceles trapezium and lined with material which is available in a standard width of 1 metre, as shown in Figure 8.21.
To achieve maximum potential capacity, the designer has to maximize the area of cross-section A(b). Show that
and that this is maximized when b = 0.5.
Transcribed Image Text:
A(b) = [(1 + b)(1 - b)]/
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Let area of crosssection be A m then 12 2 2b...View the full answer
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