If an object at temperature \(B\) is surrounded by air at temperature \(A\), it will gradually cool so that the temperature \(T\), \(t\) minutes later, is given by Newton's law of cooling:

\[T=A+(B-A) 10^{-k t}\] The constant \(k\) depends on the particular object and can be found by solving for \(k\) \[k=\frac{1}{t} \log \frac{B-A}{T-A}\]

Use this information for Problems 34-37.

The temperature of a piece of cooked chicken is initially \(100^{\circ} \mathrm{C}\). In air of \(22^{\circ} \mathrm{C}\) it cools to \(45^{\circ}\) in 30 minutes. What is the temperature in 40 minutes?