(a) Explain why compound A has a UV spectrum with considerably greater max values and intensities than are observed for ethylbenzene (b) In view of your answer to part (a), explain why the UV spectra of compounds B and C are virtually identical Et A Et Amax 256 nm (e 20,000) 283 nm (e 5,100) ...

a The two benzene rings are conjugated in compound A because there are more bonds in conjugation the ...

(a) Explain why compound A has a UV spectrum with considerably greater max values and intensities...

Question:

(a) Explain why compound A has a UV spectrum with considerably greater λ_max values and intensities than are observed for ethylbenzene. Et A Et Amax 256 nm (e = 20,000) 283 nm (e 5,100) =

(b) In view of your answer to part (a), explain why the UV spectra of compounds B and C are virtually identical. HC- H3C CH3 H3C CH3 B bimesityl Amax = 266 nm (e = 700) CH3 HC CH3 CH3 mesitylene Amax 266 nm ( = 200)