An ammeter that has internal resistance \(R_{\mathrm{am}}=0.504 \Omega\) is designed to measure a maximum current of \(I_{\max }=\) \(100 \mathrm{~mA}\). You want to use this ammeter to measure the current in a circuit that consists of a \(3.00-\mathrm{V}\) battery and a resistor that has a resistance of \(4.00 \Omega\).

(a) What problem do you encounter?

(b) How can you overcome this problem by inserting a second resistor into the circuit and rescaling the meter readout (that is, by multiplying the readout value by some constant)?