An electron is moving at speed (7.0 times 10^{10} mathrm{~m} / mathrm{s}) perpendicular to a uniform magnetic

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An electron is moving at speed \(7.0 \times 10^{10} \mathrm{~m} / \mathrm{s}\) perpendicular to a uniform magnetic field of magnitude \(0.80 \mathrm{~T}\).

(a) What is the diameter of the circular path that the electron follows? Calculate the electron's

(b) angular frequency

(c) period of motion.

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Principles And Practice Of Physics

ISBN: 9781292364797

2nd Global Edition

Authors: Eric Mazur

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Question Posted: Apr 23, 2024 04:00 AM

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An electron is moving at speed (7.0 times 10^{10} mathrm{~m} / mathrm{s}) perpendicular to a uniform magnetic

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