When a (3.0-mathrm{H}) inductor is the only element in a circuit connected to a (60-mathrm{Hz} mathrm{AC}) source
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When a \(3.0-\mathrm{H}\) inductor is the only element in a circuit connected to a \(60-\mathrm{Hz} \mathrm{AC}\) source that is delivering a maximum emf of \(160 \mathrm{~V}\), the current amplitude is \(I\). When a capacitor is the only element in a circuit connected to the same source, what must the capacitance be in order to have the current amplitude again be \(I\) ?
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