For 1.25 mol of an ideal gas, P external = P =350. 10 3 Pa.The temperature
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For 1.25 mol of an ideal gas, P external = P =350. × 103 Pa.The temperature is changed from 135°C to 21.2°C, and CV ,m = 3/2R. Calculate q, w, ΔU, and ΔH.
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U nC Vm T 125 mol 32 8314 J mol 1 K 1 408 ...View the full answer
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