731 G = 0.0731 T. If we have an unmarked magnet, how can we tell which...
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731 G = 0.0731 T. If we have an unmarked magnet, how can we tell which end is the north pole of the magnet? Hold it near a compass and the north end of the compass points at the north end of the magnet. Hold it near a compass and the north end of the compass points at the south end of the magnet. ✔Suspend it from a string and the end that points toward the geographic north pole (Santa's workshop) is the north end. Hold it near a piece of steel and the end that attracts the steel is the north end. The end that is attracted to the south end of a known magnet is the north end. The end that is attracted to the north end of a known magnet is the north end. You hold a loop, like a hula hoop, horizontal outside in the vertical rain. Take water passing downward through the loop as positive water flux. As you hold the loop, the water flux is positive with zero derivative . You then turn the loop so that it is vertical; as you do so the water flux is zero with zero derivative X. When the loop is vertical and still rotating, the water flux is positive with positive derivative 731 G = 0.0731 T. If we have an unmarked magnet, how can we tell which end is the north pole of the magnet? Hold it near a compass and the north end of the compass points at the north end of the magnet. Hold it near a compass and the north end of the compass points at the south end of the magnet. ✔Suspend it from a string and the end that points toward the geographic north pole (Santa's workshop) is the north end. Hold it near a piece of steel and the end that attracts the steel is the north end. The end that is attracted to the south end of a known magnet is the north end. The end that is attracted to the north end of a known magnet is the north end. You hold a loop, like a hula hoop, horizontal outside in the vertical rain. Take water passing downward through the loop as positive water flux. As you hold the loop, the water flux is positive with zero derivative . You then turn the loop so that it is vertical; as you do so the water flux is zero with zero derivative X. When the loop is vertical and still rotating, the water flux is positive with positive derivative
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The direction of the area vector is initially downwards since it is raining and the initial flux whe... View the full answer
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