A 0.00555–kg bullet traveling horizontally with a speed of 1.00 x 10³ m/s enters a 20.0–kg door, embedding itself 13.0 cm from the side opposite the hinges as in the figure below. The 1.00–m–wide door is free to swing on its hinges.

A door shown from above such that its hinge is on the top side of the figure with the door going down. A bullet is traveling horizontally to the right towards the door on the opposite end as the hinge.

(a) Before it hits the door, does the bullet have angular momentum relative to the door's axis of rotation?

Yes or No

(b) Is mechanical energy conserved in this collision? Answer without doing a calculation.

Yes or No

(c) At what angular speed does the door swing open immediately after the collision? (The door has the same moment of inertia as a rod with axis at one end.)_____rad/s

(d) Calculate the energy of the door–bullet system. (Enter the kinetic energy of the door–bullet system just after collision.) _____J

Determine whether the energy of the door–bullet system is less than or equal to the kinetic energy of the bullet before the collision.

less than equal or equal

Answer rating: 100% (QA)

To solve these questions well need to apply concepts from physics particularly conservation of angular momentum and conservation of mechanical energy a Before it hits the door does the bullet have ang... View the full answer