(a) A 10.0-g bullet is fired into a stationary block of wood (m = 5.00 kg)....

 

Transcribed Image Text:

(a) A 10.0-g bullet is fired into a stationary block of wood (m = 5.00 kg). The bullet gets embedded in the wood, and the speed of the wood-and-bullet combination immediately after the collision is measured to be 0.600 m/s. What was the original speed of the bullet? (b) If the block of wood is originally (prior to the collision) is at rest at the edge of a frictionless table of height 1.00 m, how far away (horizontally) away from the table's edge does the wood-and-bullet combination land? (a) A 10.0-g bullet is fired into a stationary block of wood (m = 5.00 kg). The bullet gets embedded in the wood, and the speed of the wood-and-bullet combination immediately after the collision is measured to be 0.600 m/s. What was the original speed of the bullet? (b) If the block of wood is originally (prior to the collision) is at rest at the edge of a frictionless table of height 1.00 m, how far away (horizontally) away from the table's edge does the wood-and-bullet combination land?

Answer rating: 100% (QA)

To solve this problem we can use the principle of conservation of momentum and conse... View the full answer