A ball is thrown straight up with an initial velocity of 196 feet/sec. So the height is
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Question:
A ball is thrown straight up with an initial velocity of 196 feet/sec. So the height is given by h(t)=224t-16t^2
a. find average velocity of the ball over the interval (2, 2.1)
b. when will the ball hit the ground?
c. Find the inverse function that gives the time (t) in which the ball is at the height (h) as the ball travels downward.
d. At what time will the ball be on the way back down and 540 feet above the ground?
e. make a table: find time interval and average velocity
time frames: 1 sec before hitting ground, 1/2 sec before hitting ground, 0.1, 0.01 and 0.001
f. How fast is the ball moving the instant it hit the ground?
Related Book For
University Physics with Modern Physics
ISBN: 978-0321501219
12th Edition
Authors: Hugh D. Young, Roger A. Freedman, Lewis Ford
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