A news report states that the 90% confidence interval for the mean number of daily calories...
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A news report states that the 90% confidence interval for the mean number of daily calories consumed by participants in a medical study is (2010, 2190). Assume the population distribution for daily calories consumed is normally distributed and that the confidence interval was based on a simple random sample of 18 observations. Calculate the sample mean, the margin of error, and the sample standard deviation based on the stated confidence interval and the given sample size. Use the t distribution in any calculations and round non-integer results to 4 decimal places. 1. What is the sample mean? 2100 2. Whjat is the margin ofj error? 90 3. What is the sample standard deviation? 219.4953 A news report states that the 90% confidence interval for the mean number of daily calories consumed by participants in a medical study is (2010, 2190). Assume the population distribution for daily calories consumed is normally distributed and that the confidence interval was based on a simple random sample of 18 observations. Calculate the sample mean, the margin of error, and the sample standard deviation based on the stated confidence interval and the given sample size. Use the t distribution in any calculations and round non-integer results to 4 decimal places. 1. What is the sample mean? 2100 2. Whjat is the margin ofj error? 90 3. What is the sample standard deviation? 219.4953
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PAGE Na DATE Ne have g0 1 conlidenceintow a fex the mean 2010 190 and ... View the full answer
Related Book For
An Introduction to Statistical Methods and Data Analysis
ISBN: 978-1305269477
7th edition
Authors: R. Lyman Ott, Micheal T. Longnecker
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