A truck of mass 2.00 x 103 kg is towing a large mass boulder of mass...

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A truck of mass 2.00 x 103 kg is towing a large mass boulder of mass 5.00 x 102 kg using a chain (of negligible mass). The tension in the chain is 3.00 x 10³ N. And the force of friction of the boulder is 1.20 x 10³ N. a. At what rate will the boulder accelerate? (Hint: Start with Drynamics!) b. How far will the boulder move in 3.0 s, starting from rest? m = 5.00 x 10² kg 7=3.00×10' N 1.20x10³N M=2.00x10 kg A truck of mass 2.00 x 103 kg is towing a large mass boulder of mass 5.00 x 102 kg using a chain (of negligible mass). The tension in the chain is 3.00 x 10³ N. And the force of friction of the boulder is 1.20 x 10³ N. a. At what rate will the boulder accelerate? (Hint: Start with Drynamics!) b. How far will the boulder move in 3.0 s, starting from rest? m = 5.00 x 10² kg 7=3.00×10' N 1.20x10³N M=2.00x10 kg