. The impulse response and input signal h(t) and x(t) for continuous time and h[n] and...
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. The impulse response and input signal h(t) and x(t) for continuous time and h[n] and x[n] for discrete time for an LTI system are provided as below: a. h(t) = u(t)- u(t-1), x(t) = u(t - 2) - u(t – 4), b. h(t) = u(t) - u(t-1), x(t) = cos (2nt)u(t) c. h(t) = u(t) - u(t-1), x(t) = cos (2nt) d. h(t) = u(t)- u(t-1), x(t) = cos (nt) (1-t,0 ≤ t <1 0, otherwise (2,-1≤t<0 -1, 0≤t <1 2, 1 ≤ t < 2 0, otherwise f. h(t) = u(t)- 2u(t − 2) + u(t – 5) and x(t) = e²tu(1 – t) g. h[n]u[n+ 1] - u[n-3] and x[n] = u[n] - u[n − 4] e. h(t) = {¹ and x(t) = 1) Find and sketch each LTI system's output. 2) Determine if the input signal is bounded. Justify your answer. 3) Determine if the system is BIBO stable. Justify your answer. . The impulse response and input signal h(t) and x(t) for continuous time and h[n] and x[n] for discrete time for an LTI system are provided as below: a. h(t) = u(t)- u(t-1), x(t) = u(t - 2) - u(t – 4), b. h(t) = u(t) - u(t-1), x(t) = cos (2nt)u(t) c. h(t) = u(t) - u(t-1), x(t) = cos (2nt) d. h(t) = u(t)- u(t-1), x(t) = cos (nt) (1-t,0 ≤ t <1 0, otherwise (2,-1≤t<0 -1, 0≤t <1 2, 1 ≤ t < 2 0, otherwise f. h(t) = u(t)- 2u(t − 2) + u(t – 5) and x(t) = e²tu(1 – t) g. h[n]u[n+ 1] - u[n-3] and x[n] = u[n] - u[n − 4] e. h(t) = {¹ and x(t) = 1) Find and sketch each LTI system's output. 2) Determine if the input signal is bounded. Justify your answer. 3) Determine if the system is BIBO stable. Justify your answer.
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a htutut1 xtut2ut4 1 Output ytut2ut4ut3ut5 Sketch Unit step signal from t2 to t4 2 Input is bounded ... View the full answer
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