Assume a researcher wants to compare the mean the liver enzyme Aspartate Amino Transferase (AST) levels in
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Question:
Assume a researcher wants to compare the mean the liver enzyme Aspartate Amino Transferase (AST) levels in two populations, individuals who drink alcohol and individuals who do not drink alcohol. The mean AST levels for the individuals who don't drink alcohol is 25U/L with a standard deviation of 10, and 42 individuals were in the sample. The mean AST levels for individuals who drink alcohol is 29U/L with a standard deviation of 13, and 53 individuals were in the sample. Construct and interpret a 90% confidence interval demonstrating the difference in means for those individuals who drink alcohol when compared to those who do not drink alcohol. Please help me solve this problem
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