conditions: 1. S(k) 2. S(k) 3. S(k) - Solve the following sets of recurrence relations and...

 

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conditions: 1. S(k) 2. S(k) 3. S(k) - Solve the following sets of recurrence relations and initial 10S(k-1)+9S(k-2) = 0, S(0) = 3, S(1) = 11 9S(k-1)+18S(k-2) = 0, S(0) = 0, S(1) = 3 0.25S(k-1) = 0, S(0) = 6 4. S(k)-20S(k-1) + 100S(k-2) = 0, S(0) = 2, S(1) = 50 S(k) 2S(k-1) + S(k-2) = 2, S(0) = 25, S(1) = 16 - 5. 6. S(k) - 7. S(k) - 8. S(k) 9. S(k-1)-6S(k-2)=-30, S(0) = 7, S(1) = 6 5S(k-1) = 5*, S(0) = 3 - 5S(k-1)+6S(k 2) = 2, S(0) = 1, S(1) = 0 S(k) 4S(k-1)+4S(k-2) = 3k + 2k, S(0) = 1, S(1) = 1 10. S(k) =rS(k-1)+a, S(0) = 0, r, a > 0, r1 - - 11. S(k) 4S(k-1) - 11S(k 2) + 30S(k - 3) = 0, S(0) = 0,S(1) = -35, S(2)=-85 conditions: 1. S(k) 2. S(k) 3. S(k) - Solve the following sets of recurrence relations and initial 10S(k-1)+9S(k-2) = 0, S(0) = 3, S(1) = 11 9S(k-1)+18S(k-2) = 0, S(0) = 0, S(1) = 3 0.25S(k-1) = 0, S(0) = 6 4. S(k)-20S(k-1) + 100S(k-2) = 0, S(0) = 2, S(1) = 50 S(k) 2S(k-1) + S(k-2) = 2, S(0) = 25, S(1) = 16 - 5. 6. S(k) - 7. S(k) - 8. S(k) 9. S(k-1)-6S(k-2)=-30, S(0) = 7, S(1) = 6 5S(k-1) = 5*, S(0) = 3 - 5S(k-1)+6S(k 2) = 2, S(0) = 1, S(1) = 0 S(k) 4S(k-1)+4S(k-2) = 3k + 2k, S(0) = 1, S(1) = 1 10. S(k) =rS(k-1)+a, S(0) = 0, r, a > 0, r1 - - 11. S(k) 4S(k-1) - 11S(k 2) + 30S(k - 3) = 0, S(0) = 0,S(1) = -35, S(2)=-85

Answer rating: 100% (QA)

To solve these recurrence relations we will use various methods depending on the nature of the equation 1 Sk 10Sk1 9Sk2 0 S0 3 S1 11 This is a linear homogeneous recurrence relation with constant coef... View the full answer