A 2 Using cos(a b) cos(a) cos(b) sin(a) sin(b) and cos(a b) cos(a) cos(b) sin(a) sin(b) show, for n m, that sin sin dz 0 P A 2 Using cos(a b) cos(a) cos(b) sin(a) sin(b) and cos(a b) cos(a) cos(b) sin(a) sin(b) show, for n m, that sin sin dz 0 P ...

A 2. Using cos(a + b) = cos(a) cos(b) sin(a) sin(b) and cos(a b)...

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A 2. Using cos(a + b) = cos(a) cos(b) sin(a) sin(b) and cos(a b)...

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A 2. Using cos(a + b) = cos(a) cos(b) – sin(a) sin(b) and cos(a – b) = cos(a) cos(b) + sin(a) sin(b) show, for n # m, that: sin sin dz = 0 P. A 2. Using cos(a + b) = cos(a) cos(b) – sin(a) sin(b) and cos(a – b) = cos(a) cos(b) + sin(a) sin(b) show, for n # m, that: sin sin dz = 0 P.

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