For the following cell Pb | PbCl(s) | PbCl(soln.) | AgCl(s) | Ag the potential at...

Transcribed Image Text:

For the following cell Pb | PbCl₂(s) | PbCl₂(soln.) | AgCl(s) | Ag the potential at 298 K is 0.490 V and the variation of emf with temperature is given by E = a (1.86 x 104 V K-¹) (T-25 K) Write the equation for the cell reaction and calculate AG, AH and AS for the reaction at 298 K. For the following cell Pb | PbCl₂(s) | PbCl₂(soln.) | AgCl(s) | Ag the potential at 298 K is 0.490 V and the variation of emf with temperature is given by E = a (1.86 x 104 V K-¹) (T-25 K) Write the equation for the cell reaction and calculate AG, AH and AS for the reaction at 298 K.

Answer rating: 100% (QA)

The detailed ... View the full answer