The point loads are placed at the fixed positions shown in the figure and they are...
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The point loads are placed at the fixed positions shown in the figure and they are live loads. A k a b a 1₁ B * Asc Ast Cross section 1₂ W C (centre) ƒ'c= = 38 Mpa f'ct.f = 3.5 MPa fsy = 500 MPa E = 200 GPa E = 28600 MPa 1₁ E Variables 1₁ 3 m 12 2.5 m a 45 mm b 500 mm c 450 mm Asc SC Ast 800 mm² 4000 mm² Q1) The beam carries an unfactored uniformly distributed dead load (including self-weight) of G = 2 kN/m and an unfactored uniformly distributed live load of Q = 0 kN/m. Two concentrated unfactored live loads of P = 3 kN are applied at the positions shown in the figure. (Note: The load factor for G is 1.2, and for P is 1.5. There is no uniformly distributed live load.) 1.1 Find the maximum moment of the beam. M max 1.2 Find the neutral axis distance from the top surface. If the section is governed by the linear elastic regime, the transformed area method dn = Σ yiA₁ / Σ Ai is valid. dn 1.3 Find the cracking moment. Mc = 1.4 Does this section crack? kNm (1 mark) (No answer given) (1 mark) mm (1 mark) kNm (2 mark) The point loads are placed at the fixed positions shown in the figure and they are live loads. A k a b a 1₁ B * Asc Ast Cross section 1₂ W C (centre) ƒ'c= = 38 Mpa f'ct.f = 3.5 MPa fsy = 500 MPa E = 200 GPa E = 28600 MPa 1₁ E The point loads are placed at the fixed positions shown in the figure and they are live loads. A k a b a 1₁ B * Asc Ast Cross section 1₂ W C (centre) ƒ'c= = 38 Mpa f'ct.f = 3.5 MPa fsy = 500 MPa E = 200 GPa E = 28600 MPa 1₁ E Variables 1₁ 3 m 12 2.5 m a 45 mm b 500 mm c 450 mm Asc SC Ast 800 mm² 4000 mm² Variables 1₁ 3 m 12 2.5 m a 45 mm b 500 mm c 450 mm Asc SC Ast 800 mm² 4000 mm² Q1) The beam carries an unfactored uniformly distributed dead load (including self-weight) of G = 2 kN/m and an unfactored uniformly distributed live load of Q = 0 kN/m. Two concentrated unfactored live loads of P = 3 kN are applied at the positions shown in the figure. (Note: The load factor for G is 1.2, and for P is 1.5. There is no uniformly distributed live load.) 1.1 Find the maximum moment of the beam. M max 1.2 Find the neutral axis distance from the top surface. If the section is governed by the linear elastic regime, the transformed area method dn = Σ yiA₁ / Σ Ai is valid. dn 1.3 Find the cracking moment. Mc = 1.4 Does this section crack? kNm (1 mark) (No answer given) (1 mark) mm (1 mark) kNm (2 mark) Q1) The beam carries an unfactored uniformly distributed dead load (including self-weight) of G = 2 kN/m and an unfactored uniformly distributed live load of Q = 0 kN/m. Two concentrated unfactored live loads of P = 3 kN are applied at the positions shown in the figure. (Note: The load factor for G is 1.2, and for P is 1.5. There is no uniformly distributed live load.) 1.1 Find the maximum moment of the beam. M max 1.2 Find the neutral axis distance from the top surface. If the section is governed by the linear elastic regime, the transformed area method dn = Σ yiA₁ / Σ Ai is valid. dn 1.3 Find the cracking moment. Mc = 1.4 Does this section crack? kNm (1 mark) (No answer given) (1 mark) mm (1 mark) kNm (2 mark)
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SOLUTION To solve the given problem well use the following information Dead load including selfweight G 2 kNm Live load Q 0 kNm uniformly distributed ... View the full answer
Related Book For
Income Tax Fundamentals 2013
ISBN: 9781285586618
31st Edition
Authors: Gerald E. Whittenburg, Martha Altus Buller, Steven L Gill
Posted Date:
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