Minimum cost = 50X + 10X2 + 75X3 subject to X1-X2 = 1,000 2X2+2X32,000 X ...
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Minimum cost = 50X₁ + 10X2 + 75X3 subject to X1-X2 = 1,000 2X2+2X32,000 X₁ ≤ 1,500 Solve the problem by the simplex method. Provide only the value of the basic variables at tableau #3. Notes: • Set M = 100. • Tableau #1 is the initial tableau where an inconsistency exists on row z. • Tableau #2 is the tableau where the inconsistency on row z is fixed. Minimum cost = 50X₁ + 10X2 + 75X3 subject to X1-X2 = 1,000 2X2+2X32,000 X₁ ≤ 1,500 Solve the problem by the simplex method. Provide only the value of the basic variables at tableau #3. Notes: • Set M = 100. • Tableau #1 is the initial tableau where an inconsistency exists on row z. • Tableau #2 is the tableau where the inconsistency on row z is fixed.
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