An Israeli researcher randomly assigned college students to tables of 6 people to go out to eat.
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Question:
An Israeli researcher randomly assigned college students to tables of 6 people to go out to eat. Have been to pay for their individual meals and have been to split the final check. There were a total of 4 tables in each treatment for a grand total of 48 participants.
- Create a hypothesis test in the correct statistical language. What do you suspect happened and why?
- Go to StatKey and select “Restaurant Bill”. Looking at the original sample which average bill was higher and by how much? BTW this is about $4.
- Construct a 95% confidence interval using the randomization and report a p-value for your null hypothesis. Explain how you did it.
- Repeat this exercise using the formulas. You will need to know that the sample standard deviations are 14.33 and 12.54 for Split and Individual respectively.
- Draw a conclusion incorrect terms of the original problem and explain why this is what you would expect.
Response Prompt
How did your answers differ? How were they the same? Do you agree with the conclusion that your peer picked, make sure to justify your response?
Expert Answer:
Null hypothesis The average bill per person at the end of the meal will be the same for both treatme... View the full answer
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