Question: Question 2 (20 marks) A vertical sag curve 220 m long connects a falling gradient of 5 in 100 and a rising gradient of

Question 2 (20 marks) A vertical sag curve 220 m long connects a falling gradient of 5 in 100 and a rising gradient of 3 in 100. The RL and chainage of the gradient intersection point (I) is 90m and 500.00m respectively. Calculate the reduced level (RL) of the points at 20 m interval along the curve. Chainage (m) x Offset (m) y offset Point Curve RL (m)
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To solve this problem we need to follow these steps 1 Determine the location of the vertical curves start PVI 2 Calculate the grade profile and offset... View full answer
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