## Question

# Question 2 (20 marks) A vertical sag curve 220 m long connects a falling gradient of 5 in 100 and a rising gradient of

Question 2 (20 marks) A vertical sag curve 220 m long connects a falling gradient of 5 in 100 and a rising gradient of 3 in 100. The RL and chainage of the gradient intersection point (I) is 90m and 500.00m respectively. Calculate the reduced level (RL) of the points at 20 m interval along the curve. Chainage (m) x Offset (m) y offset Point Curve RL (m)

## Step by Step Solution

There are 3 Steps involved in it

### Step: 1

To solve this problem we need to follow these steps 1 Determine the location of the vertical curves start PVI 2 Calculate the grade profile and offset...### Get Instant Access to Expert-Tailored Solutions

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### Step: 2

### Step: 3

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