Questions 1-2 The switch of the circuit shown in the figure is closed at time t...

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Questions 1-2 The switch of the circuit shown in the figure is closed at time t = 0. The capacitor is initially = 12 V, R = 50, R: uncharged and the battery has no internal resistance. E = C = 100 nF. 150 and 1. What is the current I at t = 0? (a) 360 mA (b) 120 mA 2. What is the (a) 3.6J R (c) 60 mA (d) 240 mA HH (e) 80 mA S energy lost (converts to thermal energy) through the resistor R1 until the capacitor is fully charged? (b) 7.2 J (c) 6.4 J (d) 4.8 J (e) 5.2 J R 12A Questions 1-2 The switch of the circuit shown in the figure is closed at time t = 0. The capacitor is initially = 12 V, R = 50, R: uncharged and the battery has no internal resistance. E = C = 100 nF. 150 and 1. What is the current I at t = 0? (a) 360 mA (b) 120 mA 2. What is the (a) 3.6J R (c) 60 mA (d) 240 mA HH (e) 80 mA S energy lost (converts to thermal energy) through the resistor R1 until the capacitor is fully charged? (b) 7.2 J (c) 6.4 J (d) 4.8 J (e) 5.2 J R 12A

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To solve question 1 we need to determine the current I1 through resistor R1 at the moment the switch is closed time t 0 At this instant the capacitor ... View the full answer