Set up the integral for the length of the arc of the hyperbola xy = 5...

 

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Set up the integral for the length of the arc of the hyperbola xy = 5 from the point (1,5) to the point (2, 2). (b) Use Simpson's Rule with n = 10 to estimate the arc length. SOLUTION (a) We have 5 y == X and so the arc length is = [ + (OX) dx L = dy = -[+/- 1+ -+25 dx. = 2 dy dx 25 2- 6 + / d L = 1 dx dx (b) Using Simpson's Rule with a = 1, b = 2, n = 10, Ax = 0.1, and f(x) = (1). + 4f(1.1) +2f(1.2) + 4f(1.3) + +2f(1.8) + 4f(1.9) + f(2)] (rounded to four decimal places). we have Set up the integral for the length of the arc of the hyperbola xy = 5 from the point (1,5) to the point (2, 2). (b) Use Simpson's Rule with n = 10 to estimate the arc length. SOLUTION (a) We have 5 y == X and so the arc length is = [ + (OX) dx L = dy = -[+/- 1+ -+25 dx. = 2 dy dx 25 2- 6 + / d L = 1 dx dx (b) Using Simpson's Rule with a = 1, b = 2, n = 10, Ax = 0.1, and f(x) = (1). + 4f(1.1) +2f(1.2) + 4f(1.3) + +2f(1.8) + 4f(1.9) + f(2)] (rounded to four decimal places). we have

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Set up the integral for the length of the are of the hyperbola xy 5 from the point 15 to ... View the full answer