$\mathrm{}$The moment of inertia of the pulley shown in the figure is $1=0\mathrm{.}41$ kgm$^2,$ R$1$ of the pulley $=10$cm$.$ The other end of the rope with radius is attached to the block with mass m$1=1$kg$.$ Other R$2=20$cm$.$ m$2=2$kg to the end of the rope wrapped around the radius. Its mass is asymmetrical. When the system is released 

 

a$)$Draw the free body diagram.

b$)$Calculate the angular acceleration $($a$).$

c$)$Calculating sexual accelerations $($a$1,$a$2).$

d$)$Calculate the tension forces $($T$1,$ T$2).$

Transcribed Image Text:

mi R₂ R₁ m₂ mi R₂ R₁ m₂

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The moment of inertia of the pulley is I 041kgm The inner radius ... View the full answer