Two squirrels are sitting on the rope as shown. The squirrel at A has a weight...

Transcribed Image Text:

Two squirrels are sitting on the rope as shown. The squirrel at A has a weight of 1.2 lb. The squirrel at B found less food this season and has a weight of 0.95 lb. The angles 0 and are equal to 43.5 and 52.2 respectively. Determine the tension force in each of the rope segments (T in segment AC, T2 in segment AB, and T3 in segment BD) as well as the angle a in degrees. A Note the figure may not be to scale. T = 1.32 Olb T = 1.00125 lb T3 = 1.569 lb 17.02 degrees T B A cc 030 BY NC SA 2013 Michael Swanbom The ring at B is supported in equilibrium by spring AB, a cable running through the frictionless pulley at C, and cable BD. The pulley radius is 0.0300 m, and the unstretched length of spring AB is 0.315 m. If F = 360 N and F2 = 170 N at 0 48 degrees, determine the spring constant k and the force exerted on the ring by cable BD expressed in Cartesian components. -= d C C D b F1 B k A www F2 a Values for dimensions on the figure are given in the following table. Note the figure may not be to scale. Variable Value a 0.450 m b 0.180 m 0.300 m d 0.120 m Note the figure may not be to scale. k = 708 N/m FBD = -58.209 2 + + -81.18 3) N Two squirrels are sitting on the rope as shown. The squirrel at A has a weight of 1.2 lb. The squirrel at B found less food this season and has a weight of 0.95 lb. The angles 0 and are equal to 43.5 and 52.2 respectively. Determine the tension force in each of the rope segments (T in segment AC, T2 in segment AB, and T3 in segment BD) as well as the angle a in degrees. A Note the figure may not be to scale. T = 1.32 Olb T = 1.00125 lb T3 = 1.569 lb 17.02 degrees T B A cc 030 BY NC SA 2013 Michael Swanbom The ring at B is supported in equilibrium by spring AB, a cable running through the frictionless pulley at C, and cable BD. The pulley radius is 0.0300 m, and the unstretched length of spring AB is 0.315 m. If F = 360 N and F2 = 170 N at 0 48 degrees, determine the spring constant k and the force exerted on the ring by cable BD expressed in Cartesian components. -= d C C D b F1 B k A www F2 a Values for dimensions on the figure are given in the following table. Note the figure may not be to scale. Variable Value a 0.450 m b 0.180 m 0.300 m d 0.120 m Note the figure may not be to scale. k = 708 N/m FBD = -58.209 2 + + -81.18 3) N