Use the code below to answers the following 3 questions (). #include using namespace std; int...

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Use the code below to answers the following 3 questions (). #include <iostream> using namespace std; int x (int&, int); int y(int); void z (double []); int main () { int a2, b-3, c=10; double r [3]= (1.2, 3.3, -0.2); a + x(++a, 1); by (c)+ 5; c = x (c, 1) + y (b); cout << "a = " << a << endl; cout << "b = " << b << endl; cout << "c = " << c << endl; z (r); cout << r[0] << endl; return 0; 0 1.2 int x (int & c, int 2) { } int { b = 10 y(int QQ) if (QQ 83 == 1) return 5; else if (QQ_$5 ==0) return 0; else return 1; c++; return 2; void z (double b[]) { 39. What will be output by the final cout statement in main()? a. 3.3 d. 0.2 b. e. Cannot be determined from given code C. 40. What will be output by the first cout statement in main ()? a. a=1 b. a=5 C. a=7 d. a = 3 e. a = 2 41. What will be output by the second cout statement in main ()? a. d. b=4 b=8 b. b=5 c. b=3 C. double t; t = b[0]; b[0] = b[1]; b[1] = b[2]; b[2] =t; Use the code below to answers the following 3 questions (). #include <iostream> using namespace std; int x (int&, int); int y(int); void z (double []); int main () { int a2, b-3, c=10; double r [3]= (1.2, 3.3, -0.2); a + x(++a, 1); by (c)+ 5; c = x (c, 1) + y (b); cout << "a = " << a << endl; cout << "b = " << b << endl; cout << "c = " << c << endl; z (r); cout << r[0] << endl; return 0; 0 1.2 int x (int & c, int 2) { } int { b = 10 y(int QQ) if (QQ 83 == 1) return 5; else if (QQ_$5 ==0) return 0; else return 1; c++; return 2; void z (double b[]) { 39. What will be output by the final cout statement in main()? a. 3.3 d. 0.2 b. e. Cannot be determined from given code C. 40. What will be output by the first cout statement in main ()? a. a=1 b. a=5 C. a=7 d. a = 3 e. a = 2 41. What will be output by the second cout statement in main ()? a. d. b=4 b=8 b. b=5 c. b=3 C. double t; t = b[0]; b[0] = b[1]; b[1] = b[2]; b[2] =t;

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Lets go through the code provided step by step to answer the three questions First we will evaluate ... View the full answer