Part III. Determine the content of Vit. C from the average titration volume. One serving is defined as 240 mL, and the daily value of vitamin C is set at 60 mg for non-smokers. 

Part IV. Determine the content of  Vit.  C  in each of the two fruit juice samples as you did in  Part  III.  Which sample has a higher  Vit?  C  content? How much do they differ from each other?

  

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Parts III and IV: Mass (in mg) of Vit C per mL of fruit juice: 7.50x10 molel2 B = Avg.V mL VmLjuice 1000mL Imole VitC ImoleI₂ Calculated RDV%: D= C Jx100% 60mg Vit.C Compare D to the value stated on the fruit juice bottle. X¹0⁰ 176.2g Imole VitC Mass of Vit C per serving of fruit juice. Check for the serving volume on fruit juice label. If it is 240 mL 240mL C = (B) Iserving 1000mg lg Parts III and IV: Mass (in mg) of Vit C per mL of fruit juice: 7.50x10 molel2 B = Avg.V mL VmLjuice 1000mL Imole VitC ImoleI₂ Calculated RDV%: D= C Jx100% 60mg Vit.C Compare D to the value stated on the fruit juice bottle. X¹0⁰ 176.2g Imole VitC Mass of Vit C per serving of fruit juice. Check for the serving volume on fruit juice label. If it is 240 mL 240mL C = (B) Iserving 1000mg lg

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students name institution course title instructor due date Part III Determine the content of Vit C from the average titration volume One serving is de... View the full answer