Consider the differential amplifier in Figure P11.17 with parameters (V^{+}=5 mathrm{~V}, V^{-}=-5 mathrm{~V}), and (I_{O}=0.8 mathrm{~mA}). Neglect

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Consider the differential amplifier in Figure P11.17 with parameters \(V^{+}=5 \mathrm{~V}, V^{-}=-5 \mathrm{~V}\), and \(I_{O}=0.8 \mathrm{~mA}\). Neglect base currents and assume \(V_{A}=\infty\) for all transistors. The emitter currents can be written as \(I_{E 1}=I_{S 1} e^{V_{B E 1} / V_{T}}\) and \(I_{E 2}=I_{S 2} e^{V_{B E 2} / V_{T}}\).

(a) If \(v_{1}=v_{2}=0\) and \(I_{S 1}=\) \(I_{S 2}=3 \times 10^{-15} \mathrm{~A}\), determine \(\left(v_{O 1}-v_{O 2}\right)\) for (i) \(R_{C 1}=R_{C 2}=7.5 \mathrm{k} \Omega\) and (ii) \(R_{C 1}=7.4 \mathrm{k} \Omega, R_{C 2}=7.6 \mathrm{k} \Omega\).

(b) Repeat part (a) for \(I_{S 1}=\) \(2.9 \times 10^{-15} \mathrm{~A}\) and \(I_{S 2}=3.1 \times 10^{-15} \mathrm{~A}\).

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