Find the inverse of the matrix. (mathbf{A}=left[begin{array}{cc}-L_{1} sin theta_{1}-L_{2} sin left(theta_{1}+theta_{2} ight) & -L_{2} sin left(theta_{1}+theta_{2} ight)

Question:

Find the inverse of the matrix.


\(\mathbf{A}=\left[\begin{array}{cc}-L_{1} \sin \theta_{1}-L_{2} \sin \left(\theta_{1}+\theta_{2}\right) & -L_{2} \sin \left(\theta_{1}+\theta_{2}\right) \\ L_{1} \cos \theta_{1}+L_{2} \cos \left(\theta_{1}+\theta_{2}\right) & L_{2} \cos \left(\theta_{1}+\theta_{2}\right)\end{array}\right], L_{1}, L_{2}, \theta_{1}, \theta_{2}=\) parameters

Fantastic news! We've Found the answer you've been seeking!

Step by Step Answer:

Related Book For  answer-question
Question Posted: