Consider the titration of 100.0 mL of 0.100 M HCN by 0.100 M KOH at 25
Question:
Consider the titration of 100.0 mL of 0.100 M HCN by 0.100 M KOH at 25οC. (Ka for HCN = 6.2 × 10-10.)
a. Calculate the pH after 0.0 mL of KOH has been added.
b. Calculate the pH after 50.0 mL of KOH has been added.
c. Calculate the pH after 75.0 mL of KOH has been added.
d. Calculate the pH at the equivalence point.
e. Calculate the pH after 125 mL of KOH has been added.
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Step by Step Answer:
1when 00 mL of KOH is added HCN dissociates as HCN H CN 01 0 0 01x x x Ka HCNHCN Ka xxcx Assuming x can be ignored as compared to c So above expression becomes Ka xxc so x sqrt Kac x sqrt 62101001 787...View the full answer
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Related Book For 
Chemistry
ISBN: 9781305957404
10th Edition
Authors: Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
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