The 2 radical is more stable than 1. The anti-Markovnikov orientation occurs because the bromine radical attacks

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The 2° radical is more stable than 1°. The anti-Markovnikov orientation occurs because the bromine radical attacks first to make the most stable radical, in contrast to electrophilic addition where the 11+ bonds first (see the solution to 9-15).

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Organic Chemistry

ISBN: 978-0321768414

8th edition

Authors: L. G. Wade Jr.

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Question Posted: Apr 29, 2016 12:54 PM

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The 2 radical is more stable than 1. The anti-Markovnikov orientation occurs because the bromine radical attacks

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