# Question: The following table shows the number of inquiries for a

The following table shows the number of inquiries for a sample of job opening announcements that your company has posted on two different websites, JobSite.com and Jobs!. com.

a. Using a significance level of .05, construct the appropriate hypothesis test to test a null hypothesis that there’s no difference in the average number of job inquiries that your company receives from the two websites. Assume that that the two population distributions represented here have unequal standard deviations.

b. Compare your result in part a to the result you would produce if you assume that the two population distributions have equal standard deviations.

a. Using a significance level of .05, construct the appropriate hypothesis test to test a null hypothesis that there’s no difference in the average number of job inquiries that your company receives from the two websites. Assume that that the two population distributions represented here have unequal standard deviations.

b. Compare your result in part a to the result you would produce if you assume that the two population distributions have equal standard deviations.

**View Solution:**## Answer to relevant Questions

Refer to Exercise 7. In exercise For users making video calls on Skype, the rate of dropped calls has historically been no more than 3% (. 03). In a random sample of 200 calls using Skype’s recently updated version, 11 ...Refer to Exercise 3 (interest rate and home sales), where the least squares line is ˆy =90 4x. a. Report the SSE and s y. x values. b. Tell what these measures represent. Compute and interpret the r2 and r values for the regression analysis described in Exercise 1 (Jessica’s coffee shop). Be sure to show the correct sign for r. Compute the r2 and r values for the regression analysis described in Exercise 10 (too much information). Refer to Exercise 9 where we were trying to link customer waiting time (x) to customer satisfaction (y). The boundaries for a 95% confidence interval estimate of the “population” slope here are 6.271 and 2.671. Could we ...Post your question