The rate law for the substitution reaction of 2-bromobutane and HO- in 75% ethanol and 25% water
Question:
rate = 3.20 × 10-5[2-bromobutane][HO-] + 1.5 × 10-6[2-bromobutane]
What percentage of the reaction takes place by the mechanism when these conditions
a. [HO] = 0.001 M
Fantastic news! We've Found the answer you've been seeking!
Step by Step Answer:
Related Book For
Question Posted: