What determines ΔSsurr for a process? To calculate ΔSsurr at constant pressure and temperature, we use the following equation: ΔSsurr = 2ΔH/ T. Why does a minus sign appear in the equation, and why is ΔSsurr inversely proportional to temperature?
Answer to relevant QuestionsPredict the sign of ΔSsurr for the following processes. a. H2O(l) → H2O(g) b. I2(g) → I2(s) For the reaction C2H2(g) + 4F2(g) → 2CF4(g) + H2(g) ΔSo is equal to -358 J/ K. Use this value and data from Appendix 4 to calculate the value of So for CF4(g). It is quite common for a solid to change from one structure to another at a temperature below its melting point. For example, sulfur undergoes a phase change from the rhombic crystal structure to the monoclinic crystal form ...Consider two reactions for the production of ethanol: C2H4(g) + H2O(g) → CH3CH2OH(l) C2H6(g) + H2O(g) → CH3CH2OH(l) + H2(g) Which would be more thermodynamically feasible? Why? Assume standard conditions and assume that ...Using data from Appendix 4, calculate ΔG for the reaction 2H2S(g) + SO2(g) ⇌ 3S(s) + 2H2O(g) for the following conditions at 25oC: PH2S = 1.0 × 10–4 atm PSO2 = 1.0 × 10-2 atm PH2O = 3.0 × 10-2 atm
Post your question