A series of equal end-of-quarter deposits of $1,000 extends over a period of three years. It is
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(a) F = 4($l,000)(F/i4, 12%, 3)
(b) F = $1,000(F/M,3%, 12)
(c) F = $1,000(F/A, 1%, 12)
(d) F = $1,000(F/A,3.03%, 12)
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