Apply Eqs. 7.7 and 7.10 directly to Eqs. 7.5 and 7.6 and derive the relations of Eqs.
Question:
Eq. 7.5
dα = Pdv - sdT
Eq. 7.6
dg = vdP - sdT
Eq. 7.10
dz = (∂z / ∂x)y dx + (∂z / ∂y)x dy
Eq. 7.13
(∂P/∂T)v = (∂s/∂v)T
Eq. 7.14
(∂v/∂T)P = - (∂s/∂P)T
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Related Book For
Thermodynamics for Engineers
ISBN: ?978-1133112860
1st edition
Authors: Kenneth A. Kroos, Merle C. Potter
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