Consider the following information. Jab = 5.3 Hz Jac = 8.2 Hz Jbc = 10.7 Hz (a)
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Jab = 5.3 Hz
Jac = 8.2 Hz
Jbc = 10.7 Hz
(a) How many total 1H NMR signals would you expect for the above molecule?
(b) Ha appears as a doublet of doublets (dd) at 1.32 ppm in the 1H NMR spectrum. Draw a labeled splitting tree diagram for Ha using the coupling constant values given above.
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J ab 53 Hz...View the full answer
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Related Book For 
Organic Chemistry
ISBN: 978-1118133576
11th edition
Authors: Graham Solomons, Craig Fryhle, Scott Snyder
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