Question: How can you account for the fact that 2, 2, 6-trimethylcyclohexanone yields no detectable aldol product even though it has an acidic hydrogen?
How can you account for the fact that 2, 2, 6-trimethylcyclohexanone yields no detectable aldol product even though it has an acidic α hydrogen?
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HC H3C H3C HC A HC CH3 CH3 H OH CH3 CH3 NaOH EtOH formation of enolate HO protonation HC HC HC ... View full answer
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