Solve the following linear recurrences. (a) xk+2 = 2xk - xk+1, where x0 = 1 and x1
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(a) xk+2 = 2xk - xk+1, where x0 = 1 and x1 = 2.
(b) xk+2 = 6xk - xk+1, where x0 = 1 and x1 = 1.
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a In this case x k2 2x k x k1 so Diagonalizing A gives Hence Thus for e...View the full answer
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