A grapefruit is tossed straight up with an initial velocity of 50 ft/sec. The grapefruit is 5

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A grapefruit is tossed straight up with an initial velocity of 50 ft/sec. The grapefruit is 5 feet above the ground when it is released. Its height, in feet, at time t seconds is given by

y = −16t² + 50t + 5.

How high does it go before returning to the ground?

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Applied Calculus

ISBN: 9781119275565

6th Edition

Authors: Deborah Hughes Hallett, Patti Frazer Lock, Andrew M. Gleason, Daniel E. Flath, Sheldon P. Gordon, David O. Lomen, David Lovelock, William G. McCallum, Brad G. Osgood, Andrew Pasquale

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Question Posted: Apr 11, 2023 04:08 AM

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A grapefruit is tossed straight up with an initial velocity of 50 ft/sec. The grapefruit is 5

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We want to maximize the height y of the grapefruit above ...View the full answer

Applied Calculus

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