A hot-air balloon rises vertically. At time t = 0, a ball is released from the balloon.
Question:
A hot-air balloon rises vertically. At time t = 0, a ball is released from the balloon. This graph shows the variation of the ball’s velocity v with t. The ball hits the ground at t = 4.1 s.
a. Explain how the graph shows that the acceleration of the ball is constant.
b. Use the graph to:
i. Determine the time at which the ball reaches its highest point
ii. Show that the ball rises for a further 12 m between release and its highest point
iii. Determine the distance between the highest point reached by the ball and the ground.
c. The equation relating v and t is v = 15 − 9.81t. State the significance in the equation of:
i. The number 15
ii. The negative sign.
Step by Step Answer:
Cambridge International AS And A Level Physics Coursebook
ISBN: 9781108859035
3rd Edition
Authors: David Sang, Graham Jones, Gurinder Chadha, Richard Woodside