K sp for Cu(IO 3 ) 2 is 1.4 * 10 7 . Using this value and
Question:
Ksp for Cu(IO3)2 is 1.4 * 10–7. Using this value and data in Appendix 2B, calculate E° for the half-reaction Cu(IO3)2(s) + 2 e– → Cu(s) + 2 IO3 –(aq).
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2B STANDARD POTENTIALS AT 25 °C Potentials in Electrochemical Order Reduction half-reaction Strongly oxidizing H4XeO6+ 2 H+2 e → XeO3 + 3 H₂O F₂2 e 2 F- O3 + 2 H+ 2 e → O₂ + H₂O S₂O8² +2e → 2 SO4²- Ag²+ +e → Agt Co³ + e Co²+ H₂O2+ 2 H+ 2e → 2 H₂O Aue Au Pb²+ Pb+ + 2 e 2 HCIO + 2 H+2 e → Cl₂ + 2 H₂O Cee Ce³+ 2 HBrO + 2 H+2 e Br2 + 2 H₂O MnO4 + 8 H+ + 5 e →Mn²+ + 4H₂O Mn³+ + e→ Mn²+ Au³+ + 3 e →→ Au Cl₂ + 2 e 2 CI Cr₂O7² + 14 H+ + 6 e2 Cr³+ + 7 H₂O O3 + H₂O + 2e →O₂ + 2 OH →2 H₂O O₂ + 4 H+ + 4e Eº/V +3.0 +2.87 +2.07 +2.05 +1.98 +1.81 +1.78 +1.69 +1.67 +1.63 +1.61 +1.60 +1.51 +1.51 +1.40 +1.36 +1.33 +1.24 +1.23 Reduction half-reaction NO3 + H₂O + 2 e → NO₂+ 2 OH Ti + e Ti³+ → H₂ Fe O₂ + H₂O + 2 e → HO₂ + OH Pb²+ + 2 e Pb In e Sn²+ + 2 e Sn AgIe → Ag + I Ni²+ + 2e → Ni V³+ + e → V²+ Co²+ +2e In³+ + 3 e Tl + e 2H+ +2 e Fe³+ + 3 e In → Co In Tl PbSO4 + 2 e Pb + SO4²- Ti³+ + e Ti²+ In²++eIn+ Cd²+ + 2 e Cd Cr³+e Cr²+ Fe²+ + 2 e Fe Eº/V +0.01 0.00 0, by definition -0.04 -0.08 -0.13 -0.14 -0.14 -0.15 -0.23 -0.26 -0.28 -0.34 -0.34 -0.36 -0.37 -0.40 -0.40 -0.41 -0.44
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Chemical Principles The Quest For Insight
ISBN: 9781464183959
7th Edition
Authors: Peter Atkins, Loretta Jones, Leroy Laverman
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