Let (left{x_{n}ight}_{n=1}^{infty}) be a sequence of real numbers. a. Prove that [inf _{n in mathbb{N}} x_{n} leq
Question:
Let \(\left\{x_{n}ight\}_{n=1}^{\infty}\) be a sequence of real numbers.
a. Prove that
\[\inf _{n \in \mathbb{N}} x_{n} \leq \liminf _{n ightarrow \infty} x_{n} \leq \limsup _{n ightarrow \infty} x_{n} \leq \sup _{n \in \mathbb{N}} x_{n}\]
b. Prove that
\[\liminf _{n ightarrow \infty} x_{n}=\limsup _{n ightarrow \infty} x_{n}=l\]
if and only if
\[\lim _{n ightarrow \infty} x_{n}=l\]
Fantastic news! We've Found the answer you've been seeking!
Step by Step Answer:
Related Book For
Question Posted: