Derive Eq. (5.26) for monoenergetic neutrons, that is, if the cross-sections and the flux do not depend on the incident neutron energies. It may be assumed that the scattering is isotropic.

Transcribed Image Text:

[Q + (r, E)] Y(r, Q, E) = Sext (r, Q, E) + + - JdE' JdQ'(r, E' E, Q' )(r, Q, E') (E) JdE'v (r, E') d' (r, Q', E') (5.26)