Fischer also carried out the following pair of conversions. Again, no bonds to the asymmetric carbon were
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Fischer also carried out the following pair of conversions. Again, no bonds to the asymmetric carbon were broken. Explain why this pair of conversions (but not either one alone) and the associated optical activities rule out pyramidal geometry at the asymmetric carbon, but are consistent with tetrahedral geometry.
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Neither result taken alone rules out pyramidal geometry However for an atom with two identical group...View the full answer
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