Draw the orbital energy (k.e., box) diagram for the electrons beyond the (Kr] core of the...

 

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Draw the orbital energy (k.e., box) diagram for the electrons beyond the (Kr] core of the element silver (Ag). If all the electrons are paired in the orbital energy diagram, the clement is said to be diamagnetic, meaning that atoms of the element will interact weakly with an external magnetic field. If there are any unpaired electrons, the element will be paramagnetic and will interact strongly with an external magnetic field. Is silver diamagnetic or paramagnetic? ITE OL A cation of element X has the electron configuration (XeJ6r 4"Sd" and combines chemically with chlorine to form a compound with formula XCl, What is cation X? Which of the elements in Group V has the smallest atomic radius? Explain. Write the most probable ground state electron configuration for the mercury (1) cation. What neutral element is isoelectronic with mercury (1)? Explain the trend in ionization energies for the elements whose valence electrons are in principal quantum level (i.e., period) n = 4. Draw the orbital energy (k.e., box) diagram for the electrons beyond the (Kr] core of the element silver (Ag). If all the electrons are paired in the orbital energy diagram, the clement is said to be diamagnetic, meaning that atoms of the element will interact weakly with an external magnetic field. If there are any unpaired electrons, the element will be paramagnetic and will interact strongly with an external magnetic field. Is silver diamagnetic or paramagnetic? ITE OL A cation of element X has the electron configuration (XeJ6r 4"Sd" and combines chemically with chlorine to form a compound with formula XCl, What is cation X? Which of the elements in Group V has the smallest atomic radius? Explain. Write the most probable ground state electron configuration for the mercury (1) cation. What neutral element is isoelectronic with mercury (1)? Explain the trend in ionization energies for the elements whose valence electrons are in principal quantum level (i.e., period) n = 4.

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7 Xe has 54 electrons The electronic configuration of the cation of X is Xe6s 2 5d 10 4f 14 Therefor... View the full answer