If 3/(2+ cos ?+i sin ?) = a+ib, then [(a-2) 2 +b 2 ] is (a) 0
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Question:
If 3/(2+ cos ?+i sin ?) = a+ib, then [(a-2)2+b2] is
(a) 0
(b) 1
(c) -1
(d) 2
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