We shall consider the function h given by h(n)=lg(n!) (for n>1). That is, (1) TL h(n)=lg(i)=...
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We shall consider the function h given by h(n)=lg(n!) (for n>1). That is, (1) TL h(n)=lg(i)= =lg( lg(i) i=1 i=1 Prove, from the definition of big-O (without appealing to auxiliary results), that 1. (5p) h(n) O(ng(n)) 2. (5p) h(n) 3. (5p) h(n) O(n) (n lg(n)). (Thus, given 1, also h(n) (n Ig(n)).) 72 Hint (for 2 and 3): in the sum on the right of Equation 1, more than of the terms will be > Ig(). We shall consider the function h given by h(n)=lg(n!) (for n>1). That is, (1) TL h(n)=lg(i)= =lg( lg(i) i=1 i=1 Prove, from the definition of big-O (without appealing to auxiliary results), that 1. (5p) h(n) O(ng(n)) 2. (5p) h(n) 3. (5p) h(n) O(n) (n lg(n)). (Thus, given 1, also h(n) (n Ig(n)).) 72 Hint (for 2 and 3): in the sum on the right of Equation 1, more than of the terms will be > Ig().
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